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    一文教你用python编写Dijkstra算法进行机器人路径规划

    作者:梧桐雪 时间:2021-09-19 18:29

    目录
    • 前言
    • 一、算法原理
    • 二、程序代码
    • 三、运行结果
    • 四、 A*算法:Djikstra算法的改进
    • 总结

    前言

    为了机器人在寻路的过程中避障并且找到最短距离,我们需要使用一些算法进行路径规划(Path Planning),常用的算法有Djikstra算法、A*算法等等,在github上有一个非常好的项目叫做PythonRobotics,其中给出了源代码,参考代码,可以对Djikstra算法有更深的了解。

    一、算法原理

    如图所示,Dijkstra算法要解决的是一个有向权重图中最短路径的寻找问题,图中红色节点1代表起始节点,蓝色节点6代表目标结点。箭头上的数字代表两个结点中的的距离,也就是模型中所谓的代价(cost)。

    贪心算法需要设立两个集合,open_set(开集)和closed_set(闭集),然后根据以下程序进行操作:

    • 把初始结点放入到open_set中;
    • 把open_set中代价最小的节点取出来放入到closed_set中,并且作为当前节点;
    • 把与当前节点相邻的节点放入到open_set中,如果代价更小更新代价
    • 重复2-3过程,直到找到终点。

    注意open_set中的代价是可变的,而closed_set中的代价已经是最小的代价了,这也是为什么叫做open和close的原因。

    至于为什么closed_set中的代价是最小的,是因为我们使用了贪心算法,既然已经把节点加入到了close中,那么初始点到close节点中的距离就比到open中的距离小了,无论如何也不可能找到比它更小的了。

    二、程序代码

    """
    
    Grid based Dijkstra planning
    
    author: Atsushi Sakai(@Atsushi_twi)
    
    """
    
    import matplotlib.pyplot as plt
    import math
    
    show_animation = True
    
    
    class Dijkstra:
    
        def __init__(self, ox, oy, resolution, robot_radius):
            """
            Initialize map for a star planning
    
            ox: x position list of Obstacles [m]
            oy: y position list of Obstacles [m]
            resolution: grid resolution [m]
            rr: robot radius[m]
            """
    
            self.min_x = None
            self.min_y = None
            self.max_x = None
            self.max_y = None
            self.x_width = None
            self.y_width = None
            self.obstacle_map = None
    
            self.resolution = resolution
            self.robot_radius = robot_radius
            self.calc_obstacle_map(ox, oy)
            self.motion = self.get_motion_model()
    
        class Node:
            def __init__(self, x, y, cost, parent_index):
                self.x = x  # index of grid
                self.y = y  # index of grid
                self.cost = cost
                self.parent_index = parent_index  # index of previous Node
    
            def __str__(self):
                return str(self.x) + "," + str(self.y) + "," + str(
                    self.cost) + "," + str(self.parent_index)
    
        def planning(self, sx, sy, gx, gy):
            """
            dijkstra path search
    
            input:
                s_x: start x position [m]
                s_y: start y position [m]
                gx: goal x position [m]
                gx: goal x position [m]
    
            output:
                rx: x position list of the final path
                ry: y position list of the final path
            """
    
            start_node = self.Node(self.calc_xy_index(sx, self.min_x),
                                   self.calc_xy_index(sy, self.min_y), 0.0, -1)
            goal_node = self.Node(self.calc_xy_index(gx, self.min_x),
                                  self.calc_xy_index(gy, self.min_y), 0.0, -1)
    
            open_set, closed_set = dict(), dict()
            open_set[self.calc_index(start_node)] = start_node
    
            while 1:
                c_id = min(open_set, key=lambda o: open_set[o].cost)
                current = open_set[c_id]
    
                # show graph
                if show_animation:  # pragma: no cover
                    plt.plot(self.calc_position(current.x, self.min_x),
                             self.calc_position(current.y, self.min_y), "xc")
                    # for stopping simulation with the esc key.
                    plt.gcf().canvas.mpl_connect(
                        'key_release_event',
                        lambda event: [exit(0) if event.key == 'escape' else None])
                    if len(closed_set.keys()) % 10 == 0:
                        plt.pause(0.001)
    
                if current.x == goal_node.x and current.y == goal_node.y:
                    print("Find goal")
                    goal_node.parent_index = current.parent_index
                    goal_node.cost = current.cost
                    break
    
                # Remove the item from the open set
                del open_set[c_id]
    
                # Add it to the closed set
                closed_set[c_id] = current
    
                # expand search grid based on motion model
                for move_x, move_y, move_cost in self.motion:
                    node = self.Node(current.x + move_x,
                                     current.y + move_y,
                                     current.cost + move_cost, c_id)
                    n_id = self.calc_index(node)
    
                    if n_id in closed_set:
                        continue
    
                    if not self.verify_node(node):
                        continue
    
                    if n_id not in open_set:
                        open_set[n_id] = node  # Discover a new node
                    else:
                        if open_set[n_id].cost >= node.cost:
                            # This path is the best until now. record it!
                            open_set[n_id] = node
    
            rx, ry = self.calc_final_path(goal_node, closed_set)
    
            return rx, ry
    
        def calc_final_path(self, goal_node, closed_set):
            # generate final course
            rx, ry = [self.calc_position(goal_node.x, self.min_x)], [
                self.calc_position(goal_node.y, self.min_y)]
            parent_index = goal_node.parent_index
            while parent_index != -1:
                n = closed_set[parent_index]
                rx.append(self.calc_position(n.x, self.min_x))
                ry.append(self.calc_position(n.y, self.min_y))
                parent_index = n.parent_index
    
            return rx, ry
    
        def calc_position(self, index, minp):
            pos = index * self.resolution + minp
            return pos
    
        def calc_xy_index(self, position, minp):
            return round((position - minp) / self.resolution)
    
        def calc_index(self, node):
            return (node.y - self.min_y) * self.x_width + (node.x - self.min_x)
    
        def verify_node(self, node):
            px = self.calc_position(node.x, self.min_x)
            py = self.calc_position(node.y, self.min_y)
    
            if px < self.min_x:
                return False
            if py < self.min_y:
                return False
            if px >= self.max_x:
                return False
            if py >= self.max_y:
                return False
    
            if self.obstacle_map[node.x][node.y]:
                return False
    
            return True
    
        def calc_obstacle_map(self, ox, oy):
    
            self.min_x = round(min(ox))
            self.min_y = round(min(oy))
            self.max_x = round(max(ox))
            self.max_y = round(max(oy))
            print("min_x:", self.min_x)
            print("min_y:", self.min_y)
            print("max_x:", self.max_x)
            print("max_y:", self.max_y)
    
            self.x_width = round((self.max_x - self.min_x) / self.resolution)
            self.y_width = round((self.max_y - self.min_y) / self.resolution)
            print("x_width:", self.x_width)
            print("y_width:", self.y_width)
    
            # obstacle map generation
            self.obstacle_map = [[False for _ in range(self.y_width)]
                                 for _ in range(self.x_width)]
            for ix in range(self.x_width):
                x = self.calc_position(ix, self.min_x)
                for iy in range(self.y_width):
                    y = self.calc_position(iy, self.min_y)
                    for iox, ioy in zip(ox, oy):
                        d = math.hypot(iox - x, ioy - y)
                        if d <= self.robot_radius:
                            self.obstacle_map[ix][iy] = True
                            break
    
        @staticmethod
        def get_motion_model():
            # dx, dy, cost
            motion = [[1, 0, 1],
                      [0, 1, 1],
                      [-1, 0, 1],
                      [0, -1, 1],
                      [-1, -1, math.sqrt(2)],
                      [-1, 1, math.sqrt(2)],
                      [1, -1, math.sqrt(2)],
                      [1, 1, math.sqrt(2)]]
    
            return motion
    
    
    def main():
        print(__file__ + " start!!")
    
        # start and goal position
        sx = -5.0  # [m]
        sy = -5.0  # [m]
        gx = 50.0  # [m]
        gy = 50.0  # [m]
        grid_size = 2.0  # [m]
        robot_radius = 1.0  # [m]
    
        # set obstacle positions
        ox, oy = [], []
        for i in range(-10, 60):
            ox.append(i)
            oy.append(-10.0)
        for i in range(-10, 60):
            ox.append(60.0)
            oy.append(i)
        for i in range(-10, 61):
            ox.append(i)
            oy.append(60.0)
        for i in range(-10, 61):
            ox.append(-10.0)
            oy.append(i)
        for i in range(-10, 40):
            ox.append(20.0)
            oy.append(i)
        for i in range(0, 40):
            ox.append(40.0)
            oy.append(60.0 - i)
    
        if show_animation:  # pragma: no cover
            plt.plot(ox, oy, ".k")
            plt.plot(sx, sy, "og")
            plt.plot(gx, gy, "xb")
            plt.grid(True)
            plt.axis("equal")
    
        dijkstra = Dijkstra(ox, oy, grid_size, robot_radius)
        rx, ry = dijkstra.planning(sx, sy, gx, gy)
    
        if show_animation:  # pragma: no cover
            plt.plot(rx, ry, "-r")
            plt.pause(0.01)
            plt.show()
    
    
    if __name__ == '__main__':
        main()
    
    

    三、运行结果

    四、 A*算法:Djikstra算法的改进

    Dijkstra算法实际上是贪心搜索算法,算法复杂度为O( n 2 n^2 n2),为了减少无效搜索的次数,我们可以增加一个启发式函数(heuristic),比如搜索点到终点目标的距离,在选择open_set元素的时候,我们将cost变成cost+heuristic,就可以给出搜索的方向性,这样就可以减少南辕北辙的情况。我们可以run一下PythonRobotics中的Astar代码,得到以下结果:

    总结

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