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    算法探索之路:leetcode 232. 用栈实现队列 python3

    作者:[db:作者] 时间:2021-08-14 18:08

    【原题连接】
    本质是 2个栈实现一个队列
    代码如下:

    class MyQueue:
    
        def __init__(self):
            """
            Initialize your data structure here.
            """
            self.stack1 = []
            self.stack2 = []
            
    
        def push(self, x: int) -> None:
            """
            Push element x to the back of queue.
            """
            self.stack1.append(x)
            
    
        def pop(self) -> int:
            """
            Removes the element from in front of queue and returns that element.
            """
            if len(self.stack2) == 0 and len(self.stack2) == 0:
                return None
            if len(self.stack2) == 0:
                while self.stack1:
                    self.stack2.append(self.stack1.pop())
            return self.stack2.pop()
            
    
        def peek(self) -> int:
            """
            Get the front element.
            """
            if len(self.stack2) == 0:
                while self.stack1:
                    self.stack2.append(self.stack1.pop())
            return self.stack2[-1]
            
    
        def empty(self) -> bool:
            """
            Returns whether the queue is empty.
            """
            return len(self.stack1) == 0 and len(self.stack2) == 0
            
    
    
    # Your MyQueue object will be instantiated and called as such:
    # obj = MyQueue()
    # obj.push(x)
    # param_2 = obj.pop()
    # param_3 = obj.peek()
    # param_4 = obj.empty()
    

    另外参考用2个队列实现栈
    用列表实现栈、队列

    cs