当前位置 博文首页 > 向日葵的专属太阳：Python opencv医学处理
题目描述
利用opencv或其他工具编写程序实现医学处理。
实现过程
# -*- coding: utf-8 -*-
'''
作者 : 丁毅
开发时间 : 2021/5/9 16:30
'''
import cv2
import numpy as np
# 图像细化
def VThin(image, array):
rows, cols = image.shape
NEXT = 1
for i in range(rows):
for j in range(cols):
if NEXT == 0:
NEXT = 1
else:
M = int(image[i, j - 1]) + int(image[i, j]) + int(image[i, j + 1]) if 0 < j < cols - 1 else 1
if image[i, j] == 0 and M != 0:
a = [0]*9
for k in range(3):
for l in range(3):
if -1 < (i - 1 + k) < rows and -1 < (j - 1 + l) < cols and image[i - 1 + k, j - 1 + l] == 255:
a[k * 3 + l] = 1
sum = a[0] * 1 + a[1] * 2 + a[2] * 4 + a[3] * 8 + a[5] * 16 + a[6] * 32 + a[7] * 64 + a[8] * 128
image[i, j] = array[sum]*255
if array[sum] == 1:
NEXT = 0
return image
def HThin(image, array):
rows, cols = image.shape
NEXT = 1
for j in range(cols):
for i in range(rows):
if NEXT == 0:
NEXT = 1
else:
M = int(image[i-1, j]) + int(image[i, j]) + int(image[i+1, j]) if 0 < i < rows-1 else 1
if image[i, j] == 0 and M != 0:
a = [0]*9
for k in range(3):
for l in range(3):
if -1 < (i-1+k) < rows and -1 < (j-1+l) < cols and image[i-1+k, j-1+l] == 255:
a[k*3+l] = 1
sum = a[0]*1+a[1]*2+a[2]*4+a[3]*8+a[5]*16+a[6]*32+a[7]*64+a[8]*128
image[i, j] = array[sum]*255
if array[sum] == 1:
NEXT = 0
return image
array = [0, 0, 1, 1, 0, 0, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1,\
1, 1, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1,\
0, 0, 1, 1, 0, 0, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1,\
1, 1, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1,\
1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,\
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,\
1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 1, 1, 1, 0, 1,\
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,\
0, 0, 1, 1, 0, 0, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1,\
1, 1, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1,\
0, 0, 1, 1, 0, 0, 1, 1, 1, 1, 0, 1, 1, 1,
