本文实例讲述了Python打印scrapy蜘蛛抓取树结构的方法。分享给大家供大家参考。具体如下：
通过下面这段代码可以一目了然的知道scrapy的抓取页面结构，调用也非常简单
#!/usr/bin/env python
import fileinput, re
from collections import defaultdict
def print_urls(allurls, referer, indent=0):
urls = allurls[referer]
for url in urls:
print ' '*indent + referer
if url in allurls:
print_urls(allurls, url, indent+2)
def main():
log_re = re.compile(r'<GET (.*?)> \(referer: (.*?)\)')
allurls = defaultdict(list)
for l in fileinput.input():
m = log_re.search(l)
if m:
url, ref = m.groups()
allurls[ref] += [url]
print_urls(allurls, 'None')
main()
希望本文所述对大家的Python程序设计有所帮助。
jsjbwy
