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    shell打印给定日期的日历

    作者:小他529 时间:2021-02-08 09:02

    学习shell有一段时间了,一直没有机会练手,看到同事发了一张照片,控制台显示了当月的日历,是用Python实现的,感觉挺好玩,所以准备用shell来实现一个,搞了一下午,终于搞定。

    打印本月的日期

    #! /bin/bash
    #设置字体颜色
    tiffcolor="\033[0;35m"
    menucolor="\033[0;33m"
    todaycolor="\033[0;35;44m"
    start="\033[0m"
    
    #计算各个日期
    month=`date +%m`
    day=`date +%d`
    year=`date +%Y`
    weekday=`date -d "$year-$month-01" +%w`
    nextmonth=`expr $month + 1`
    today=`date +%d`
    #计算本月有多少天
    differ=$(( ($(date -d "$year-$nextmonth-01" +%s) - $(date +%s))/(24*60*60) )) 
    days=`expr $differ + $day`
    
    #打印标题
    echo -en "${menucolor}"
    echo -en "\t  $year $month\n"
    echo "SUN MON TUE WEN THU FRI SAT"
    echo -en "${start}"
    
    #打印空格
    if [ $weekday -ne 0 ];then
    for((i=1;i<=$weekday;i++))
    do
      echo -n "  "
      echo -n " "
    done
    fi
    
    #打印日期
    for((i=1;i<=$days;i++))
    do
      printf "%s" " "
      echo -en "${tiffcolor}"
      #今天高亮显示
        if [ $today -eq $i ];then
          echo -en "${todaycolor}"
        fi
      printf "%2d" $i
      echo -en "${start}"
      echo -en " "
      if [ $((($weekday+$i)%7)) == 0 ];then
        echo ""
      fi
    #  printf "%3d " $i
    done
    echo ""

    执行结果:

    扩展:给定任意日期,打印当月的日期

    #! /bin/bash
    #date=$1
    tiffcolor="\033[0;35m"
    menucolor="\033[0;33m"
    todaycolor="\033[0;35;44m"
    start="\033[0m"
    
    
    if [ $# -ne 1 ];then
      echo "plz input the date"
      exit 1
    fi
    date=$1
    count=`echo $date |grep -o '-'|wc -l`
    if [ $count -ne 2 ];then
      echo "plz input correct date"
      exit 1
    fi
    year=`echo $date|cut -d "-" -f 1`
    month=`echo $date|cut -d "-" -f 2`
    day=`echo $date|cut -d "-" -f 3`
    expr $year + $month + $day + 0 &>/dev/null
    if [ $? -ne 0 ];then
      echo "plz input a correct date"
      exit 1
    elif [ $month -gt 12 -o $month -eq 0 ];then
      echo "plz input the month between 1 and 12"
      exit 1
    elif [ $day -gt 31 -o $day -eq 0 ];then
      echo "plz input the day between 1 and 31"
      exit 1
    fi
    
    #nextmonth=$(( $month + 1))
    #month=`date -d "$date" +%m`
    #day=`date -d "$date" +%d`
    #year=`date -d "$date" +%Y`
    weekday=`date -d "$year-$month-01" +%w`
    if [ $month -eq 12 ];then
      newmonth=1
      newyear=`expr $year + 1`
    else
      newyear=$year
      #nextmonth= expr $month + 1
      newmonth=`expr $month + 1`
    fi
    days=$(( ($(date -d "${newyear}-${newmonth}-01" +%s) - $(date -d "$year-$month-01" +%s))/(24*60*60) )) 
    #echo $days
    echo -en "${menucolor}"
    echo -en "\t  $year $month\n"
    echo "SUN MON TUE WEN THU FRI SAT"
    echo -en "${start}"
    
    if [ $weekday -ne 0 ];then
    for((i=1;i<=$weekday;i++))
    do
      echo -n "  "
      echo -n " "
    done
    fi
    
    
    for((i=1;i<=$days;i++))
    do
      printf "%s" " "
      echo -en "${tiffcolor}"
        if [ $day -eq $i ];then
          echo -en "${todaycolor}"
        fi
      printf "%2d" $i
      echo -en "${start}"
      echo -en " "
      if [ $((($weekday+$i)%7)) == 0 ];then
        echo ""
      fi
    #  printf "%3d " $i
    done
    echo ""

    执行结果:

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