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    java8如何通过Lambda处理List集合

    栏目:代码类 时间:2020-01-22 15:05

    这篇文章主要介绍了java8如何通过Lambda处理List集合,文中通过示例代码介绍的非常详细,对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下

    Java 8新增的Lambda表达式,我们可以用简洁高效的代码来处理List。

    1、遍历

    public static void main(String[] args) {
        List<User> userList = Lists.newArrayList();
    
        User user1 = new User(1L, "张三", 24);
        User user2 = new User(2L, "李四", 27);
        User user3 = new User(3L, "王五", 21);
    
        userList.add(user1);
        userList.add(user2);
        userList.add(user3);
    
        userList.stream().forEach(user ->{
          System.out.println(user.getName());
        });
    
      }

    运行结果:

    2、list转为Map

    public static void main(String[] args) {
        List<User> userList = Lists.newArrayList();//存放user对象集合
    
        User user1 = new User(1L, "张三", 24);
        User user2 = new User(2L, "李四", 27);
        User user3 = new User(3L, "王五", 21);
    
        userList.add(user1);
        userList.add(user2);
        userList.add(user3);
    
        //ID为key,转为Map
        Map<Long,User> userMap = userList.stream().collect(Collectors.toMap(User::getId, a -> a,(k1, k2)->k1));
        System.out.println(userMap);
    
      }

    运行结果:

    3、将List分组:List里面的对象元素,以某个属性来分组

    public static void main(String[] args) {
        List<User> userList = Lists.newArrayList();//存放user对象集合
    
        User user1 = new User(1L, "张三", 24);
        User user2 = new User(2L, "李四", 27);
        User user3 = new User(3L, "王五", 21);
        User user4 = new User(4L, "张三", 22);
        User user5 = new User(5L, "李四", 20);
        User user6 = new User(6L, "王五", 28);
    
        userList.add(user1);
        userList.add(user2);
        userList.add(user3);
        userList.add(user4);
        userList.add(user5);
        userList.add(user6);
    
        //根据name来将userList分组
        Map<String, List<User>> groupBy = userList.stream().collect(Collectors.groupingBy(User::getName));
        System.out.println(groupBy);
    
      }

    运行结果:

    4、过滤:从集合中过滤出来符合条件的元素

    public static void main(String[] args) {
        List<User> userList = Lists.newArrayList();//存放user对象集合
    
        User user1 = new User(1L, "张三", 24);
        User user2 = new User(2L, "李四", 27);
        User user3 = new User(3L, "王五", 21);
        User user4 = new User(4L, "张三", 22);
        User user5 = new User(5L, "李四", 20);
        User user6 = new User(6L, "王五", 28);
    
        userList.add(user1);
        userList.add(user2);
        userList.add(user3);
        userList.add(user4);
        userList.add(user5);
        userList.add(user6);
    
    
        //取出名字为张三的用户
        List<User> filterList = userList.stream().filter(user -> user.getName().equals("张三")).collect(Collectors.toList());
        filterList.stream().forEach(user ->{
          System.out.println(user.getName());
        });
    
      }